Question
A sample of an unknown material weighs $300.0 \mathrm{N}$ in air and $200.0 \mathrm{N}$ when submerged in an alcohol solution with a density of $0.70 \times 10^{3} \mathrm{kg} / \mathrm{m}^{3}$. What is the density of the material? (See Sample Problem 9A.)
Step 1
Step 1: The weight of the sample in air is given by the equation $mg = 300 \, \text{N}$, where $m$ is the mass of the sample and $g$ is the acceleration due to gravity. Show more…
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see Sample Problem $A.$ A sample of an unknown material weighs $300.0 \mathrm{N}$ in air and $200.0 \mathrm{N}$ when submerged in an alcohol solution with a density of $0.70 \times 10^{3} \mathrm{kg} / \mathrm{m}^{3} .$ What is the density of the material?
A sample of an unknown material weighs 300 N in air and 200 N when submerged in an alcohol solution with a density of 0.70 x 10^3 kg/m^3. What is the material?
A sample of an unknown material appears to weigh 275 N in air and 195 N when immersed in alcohol of specific gravity 0.700. (a) What is the volume of the material? m^3 (b) What is the density of the material? kg/m^3
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