00:02
Right.
00:03
This problem is another ideal gas equation problem.
00:08
So we are going to be using pv equals nrt.
00:15
Reading through the problem, we see that we are trying to solve for volume in this problem, volume in liters.
00:25
Looking at the given information, we see that we are given a pressure in millimeters of mercury, 531 millimeters of mercury.
00:38
If we think about the values for the universal gas constant that we've been given, we know that we have one that measures in atmospheres and one that measures in tor.
00:51
So we need to get this unit, millimeters of mercury, into one of those, either atmospheres or tor.
00:58
I'm going to select tor because i know that millimeters of mercury and tor are the same thing.
01:04
We know that 760 millimeters of mercury are the same as 760 tor.
01:16
That means the numerical value doesn't change.
01:18
We still have 531, but now it's in the unit tour.
01:27
After pressure, we are given a temperature.
01:30
It is already in kelvin.
01:32
So i'm just going to record it here, 291 kelvin.
01:37
And then for number of molecules.
01:39
I'm sorry, for number of moles, rather.
01:42
We are not given moles, but we are given mass.
01:46
We are given 10 .2 grams of neon.
01:54
Well, we know that to use our ideal gas equation, n represents moles.
01:59
So i need to convert this to moles before i can plug it into that equation.
02:05
We know from our previous units that we can convert from grams to moles by using the molar mass.
02:11
In every mole of neon, there is 20 .18 grams...