00:01
Okay, this will be a little long answer because we have three parts in the question.
00:08
So yeah, let's start.
00:12
First of all, we start with a little basic.
00:16
We have a sample of sulfur 35s16, which have a disintegration rate.
00:25
So this integration rate, which is equal.
00:34
To 1 multiplied 10 raise to par 3 atoms per minute.
00:42
Now we know that there's a formula nt divided by n0 equals to half raise to power n.
00:54
Let's remember this formula as formula number one.
00:58
Here the disintegration rate after n half lives is represented by n t and n.
01:07
Not represents the initial disintegration rate.
01:12
So we take log on the both sides.
01:16
Now we take log on both sides...