00:01
Okay, so we're asked to write the formula of the products and determine by what mechanism this occurs.
00:10
So we have s2 chlorobutene.
00:16
So this group is 1, the ethyls 2, the methyl is 3, and group number 4 is on the wedge.
00:25
So it should go clockwise, but because group number 4 is on the wedge, it goes in the opposite direction, which is s.
00:37
And reacting with water.
00:57
So water is a polar puritic solvent, and we have a secondary alkaliad.
01:18
So because of these two factors, we have the sn1 -e -1 mechanism, but the s -n -1 is the major product.
01:30
So i'll draw that out first.
01:37
So s -n -1 occurs in two steps.
01:39
The first is for the aquilite to leave.
01:44
So we have a secondary carbocation, then water can attack from or from the front.
01:56
Leading to this and the oxygen has a positive charge because it donated a pair of electrons that were negative.
02:26
The next step is for the chlorine that was expelled in the first step to act as a nucleophile and so this is step number two this is three.
02:43
The chlorine acts as a nucleophile grabs a hydrogen and the electrons get back to the oxygen...