00:01
Hi, everybody.
00:01
So this question is asking us, is there any liquid water at the final state, find the heat transfer in the process, okay? so first we need to do the volume of the liquid.
00:15
And we got one times 0 .001.
00:19
So we get 0 .001 meter cube.
00:23
And now we have the volume of the gas, which is v minus the liquid.
00:30
We're just going to make that l.
00:32
And so we have 5 minus 0 .001, and we get 4 .99 meter cubed.
00:41
And you could technically round it up to 5, but let's just keep it at that.
00:45
So we have initial relatively humidity at 5 equals 100%.
00:52
And we have p1, the p liquid, equals the p gas of the initial state.
01:02
And here, that's going to be 2 .339k pascels.
01:10
And so we can find the absolute humidity at 1 as 0 .622 pv1 divided by p minus pv1.
01:21
So here we have 0 .622 and 2 .339, 100 minus 2 .330.
01:32
And we get 0 .0149 and that's the ratio and now we need to find the mass of air so we have massive air equals 100 minus 2 .339 okay and now we have 4 .999 999 so we have the volume okay and we have 0 .287 at times 20 plus 273.
02:02
15 and and that's just converting it to kelvin, the temperature of kelvin's.
02:05
So we get 5 .802 kilograms.
02:12
And now we need to find the mass of volume 1 equals this guy right here, the humidity times mass air.
02:25
And we get 0 .0149 times 5 .802.
02:33
And in this we get 0 .0864 kilograms.
02:39
Okay.
02:41
And now we can do the ideal gas ratio.
02:44
So we have pav1 divided by t1 equals pa2 v2.
02:52
T2...