Given that \(k = 1.4\), \(R = 1716 \, \text{ft} \, \text{lbf/lbm} \, \text{R}\), and \(T = 68^{\circ}F = 520^{\circ}R\), we can substitute these values into the formula to get:
\[a = \sqrt{1.4 \times 1716 \times 520} = 1116.5 \, \text{ft/s}\]
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