Question
A schlieren photo of a bullet moving through air (see Video $\mathrm{V} 11.10$ at 14.7 psia and $68^{\circ} \mathrm{F}$ indicates a Mach cone angle of $28^{\circ} .$ How fast was the bullet moving in:(a) $\mathrm{m} / \mathrm{s}$(b) $\mathrm{ft} / \mathrm{s}$(c) mph?
Step 1
The Mach cone angle (θ) is related to the Mach number (M) by the equation: sin(θ) = 1 / M Given the Mach cone angle of 28°, we can find the Mach number: sin(28°) = 1 / M M = 1 / sin(28°) M ≈ 2.08 Show more…
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