00:01
In this problem, we're given a table where it categorizes 250 employees of a school into their tasks and their gender.
00:09
So part a is the probability that they're female.
00:12
So there are 56 plus 26 plus 18 females.
00:16
So 100 out of the 250 are female.
00:22
So 100 over 250.
00:24
That'll be 0 .4 as the probability.
00:28
The next part, probability that they're female and teacher.
00:32
Well, there are 56 of them.
00:35
So 56 over 250.
00:39
And when we reduce it, turn it into a decimal, that'll be 0 .224.
00:45
In the next one, probability that they're female or not in an administrative rule.
00:51
There are only 14 male administrators.
00:54
So if we just take the complement, 250 minus 14.
00:57
That'll be 236 people that are females or non -administrators over 250 and that'll equal to 0 .944.
01:13
And the last one in part a, probability that they are not female and an administrator over the probability of being an administrator.
01:27
So not female and administrator would be really male and administrator.
01:32
So 14 over 250.
01:36
And probability of being an administrator, 14 plus 26.
01:40
There are 40 of them.
01:42
So that will be times 250 over 40 when you reciprocate the fraction because of the division.
01:47
So that will be 14 over 40 and that will give us 0 .35.
01:57
In part b, we want to identify some events.
02:01
That are independent to f, so independent to being female and mutually exclusive to being female.
02:07
The mutually exclusive one is an easier one to look at in this table...