Question
A sealed flask contains $0.55 \mathrm{~g}$ of water at $28^{\circ} \mathrm{C}$. The vapor pressure of water at this temperature is $28.36 \mathrm{mmHg}$. What is the minimum volume of the flask in order that no liquid water be present in the flask?
Step 1
Since we want to find the volume, we rearrange the equation to solve for $V$, which gives us $V = \frac{nRT}{P}$. Show more…
Show all steps
Your feedback will help us improve your experience
Adriano Chikande and 52 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A sealed flask contains 0.55 $\mathrm{g}$ of water at $28^{\circ} \mathrm{C}$ . The vapor pressure of water at this temperature is 28.35 $\mathrm{mm} \mathrm{Hg} .$ What is the minimum volume of the flask in order that no liquid water be present in the flask?
A sealed flask contains 0.55 g of water at 28 C. The vapor pressure of water at this temperature is 28.36 mmHg. What is the minimum volume of the flask in order that there is no liquid water present in the flask?
A sealed flask contains 0.50 g of water at 28 ∘C. The vapor pressure of water at this temperature is 28.36 mmHg. What is the minimum volume of the flask in order that no liquid water be present in the flask?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD