Question
A second's pendulum clock having steel wire is calibrated at $20^{\circ} \mathrm{C}$. When temperature is increased to $30^{\circ} \mathrm{C}$, then how much time does the clock lose or gain in one week ? $\left[\alpha_{\text {steel }}=1.2 \times 10^{-5}\left({ }^{\circ} \mathrm{C}\right)^{-1}\right]$(a) $0.3628 \mathrm{~s}$(b) $3.626 \mathrm{~s}$(c) $362.8 \mathrm{~s}$(d) $36.28 \mathrm{~s}$
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