Problem

The figure shows a circular arc of length $ s $ a…

02:02

Problem 56 Medium Difficulty

A semicircle with diameter $ PQ $ sits on an isosceles triangle $ PQR $ to form a region shaped like a two-dimensional ice-cream cone, as shown in the figure. If $ A(\theta) $ is the area of the semicircle and $ B(\theta) $ is the area of the triangle, find
$ \displaystyle \lim_{x \to 0^+} \frac {A(\theta)}{B(\theta)} $

Answer

$=0$

October 23, 2020

Finally, now Im done with my homework

David Base G.

October 23, 2020

That was not easy, glad this was able to help

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Video Transcript

you know, it's clear. So when you right here. So we have the radius of us on my circle. This is equal to half of the base of the triangle, and we're using sign data over to Minister. Hi, pot news. And we have the area love us in my circle, which is half of Pyre Square. We're taking the base of data, which is equal to two times one, huh? I'm send sign data over to times 10. Co sign data over to which is the height simplified. We get 100 sign beta over to co sign, you know, over to and when we plug in values for a of data and be of data, we get the limit. That's data approaches. Sarah from the positive side, A F data over B data is equal to 50. Pie signed square data over to over 100. Signed data over to co sign data over to and we've simplify one more time to get data approaching. Zero from the positive pi. Sign data over to over to co sign data over to which is equal to zero

Clarissa N.

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Problem

The figure shows a circular arc of length $ s $ a…

Problem 56 Medium Difficulty

Answer

$=0$

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