0:00
Hi, everybody.
00:01
So we're asked the student process to be reversible in atabatic and determine the minimum inlet air pressure in the fiber bundle.
00:12
So for this, we're just going to find the number of moles.
00:22
So we've got an n2 and n2 plus n02.
00:28
And we got 0 .05 equals n02, 0 .79 plus n02.
00:38
I'm going to solve for n02, and we get 0 .04557.
00:47
So now we can do n021, which is n02 plus n023.
00:55
This is 0 .21 equals 0 .04157 plus n023, and n023 is 0 .16843.
01:13
And your n mix equals n02 plus n2, and n2.
01:20
We get 0 .0457 plus 0 .0257 plus 0 .0257 plus 0 .0.
01:26
0 .79 and we get 0 .833157.
01:31
Now we're just going to scroll down.
01:35
Okay, so now we have the entropy mixes, so x mix 3 plus x mix 2 plus minus s mix 1 equals 0.
01:53
So from this, we can write in 023, of p3 of p1 minus n mix 2 r l n p2 over p1 minus n n 2 r ln b2 over p1 minus n n 2 3 r ln y o 1 equals 0 oops, and i forgot to these same brackets.
02:44
We have n2, l -n -y -n -1 -2 minus n -o -2, l -n -y -o -2...