00:01
Before we do anything, let's get the voltage rms from the voltage amplitude.
00:05
So the voltage rms is equal to the voltage amplitude over the square of 2.
00:10
And plugging in the value here, which is 45 volts, we get a voltage rms of 31 .8 volts.
00:16
And we'll set that aside for now.
00:20
So the power factor that they're referring to in part a is equal to cosine of phi, where phi is the phase angle, and the phase angle is given by, well, the tangent of the phase angle, i should say, is given by the reactance of the inductor, minus the reactance of the capacitor over the resistance.
00:43
And so let's figure out what these quantities are.
00:46
The reactance of the inductor is equal to omega times l, and plugging in the values that we're given, 360 radiance per second.
00:57
And for l, we have 15 times 10 to the minus third henry's.
01:02
And so this is equal to 5 .4 oms.
01:06
And then for xc, we know that.
01:07
Know it to be 1 over omega c.
01:10
And so this is equal to 1 over 360 radiance per second times the capacitance, which is 3 .5 times 10 to the minus 6 ferrets.
01:25
And so this gives 794 oms.
01:30
And so now we can plug these two things along with the resistance that they give us to figure out what this phi is.
01:39
We have to take an inverse tangent at the end.
01:42
But if you do that, you get that phi is negative.
01:44
72 .4 degrees.
01:47
And so now we can take the cosine of this to figure out what the power factor is.
01:52
Since this here is the power factor.
01:57
And we get that the power factor when we take the cosine is equal to 0 .302.
02:09
In part b, we're going to need to calculate the impedance in order to calculate the power going through the circuit here.
02:17
And so let's go ahead and calculate that.
02:19
I get z is equal to the square root of r squared.
02:25
Plus xl minus xc...