Question
A series $R L C$ circuit has a resistance of 22.0$\Omega$ and an impedance of 80.0$\Omega$ . If the rms voltage applied to the circuit is $160 . \mathrm{V},$ what average power is delivered to the circuit?
Step 1
The rms current is given by the rms voltage divided by the impedance, $Z$. This can be written as: \[I_{rms} = \frac{V_{rms}}{Z}\] Substituting the given values, we get: \[I_{rms} = \frac{160V}{80.0\Omega} = 2.0A\] Show more…
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A series $R L C$ circuit has a resistance of 22.0$\Omega$ and an impedance of 80.0$\Omega$ . If the rms voltage applied to the circuit is $160 \mathrm{V},$ what average power is delivered to the circuit?
A series $R L C$ circuit has a resistance of $45.0 \Omega$ and an impedance of $75.0 \Omega$. What average power is delivered to this circuit when $\Delta V_{\text {rms }}=210 \mathrm{V?}$
A series $R L C$ circuit has a resistance of 45.0$\Omega$ and an impedance of 75.0$\Omega$ . What average power is delivered to this circuit when $\Delta V_{\mathrm{rms}}=210 \mathrm{V} ?$
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