00:01
A series rlc circuit with arc resistance equal 2 kilo -e -em, inductance equal 40 milliehandle and the capacitance is 1 micro -farrad, then calculate the impedance at resonance and at 1 4th, 1 half, twice and 4 times the resonant frequency.
00:26
Calculating the impedance of the c's rlc circuit, z equals zr plus zl plus zc, which will be equals to r plus j omega l plus 1 by j omega c.
00:39
This can be written as r plus j omega l.
00:43
The resonant frequency is given by 1 by root lc, substituting the value 1 by root of 40 into 10 raise to the power minus 3 multiply 1 into 10 raised to the power minus 6.
00:55
This will be equals to 5 kilo radian per second.
01:01
Now calculating the impedance at the circuit at resonance omega equals to omega -not, z omega -not - equals r plus j, omega -0 -l minus 1 by omega -0c.
01:14
Substituting the values 2 ,000 plus j into 5 into 10 raised to the power 3, multiply, 40 into 10 raised to the power minus 3 minus 1 by 5 into 10 raised to the power 3 multiply 1 into 10 raised to the power minus 6.
01:36
1 into 10 raised to the power minus 6.
01:40
Then the value for the impedance will be 2 kilo oom.
01:45
This is the impedance at resonance...