00:01
For this problem on the topic of geometric optics, we have a shallow glass dish that is 4 centimeters wide at the bottom, as we can see in the figure.
00:09
When the observer's eyes positioned as shown in this figure, they see the edge of the bottom of the empty dish.
00:17
When the dish is filled with water, they see the center of the bottom of the dish.
00:22
Using this information, we want to find the height of the dish, which is h.
00:26
So we can see that the tan of angle theta 1 is equal to 4 centimeters divided by h.
00:39
And the tan of the angle theta 2 is equal to 2 centimeters over h.
00:51
And the tan squared of angle theta 1 is equal to 2 times the tan of theta 2 all squared.
01:10
So this is 4 times the tan of theta 2 squared.
01:19
And so we can write this as sine squared theta 1 divided by cosine squared theta 1, which is 1 minus sine squared theta 1 is equal to 4 into sine squared of theta 2 divided by 1 minus sine squared of theta 2.
01:48
We'll call this equation number 1.
01:52
Now we can apply snell's law and we get n1 sine theta 1 is equal to n2 sine theta 2.
02:07
So we get sine theta 1...