A shear spring is made by bonding the rubber annulus to a rigid fixed ring and a plug. When an axial load $\mathbf{P}$ is placed on the plug, show that the slope at point $y$ in the rubber is $d y / d r=-\tan \gamma=-\tan (P /(2 \pi h G r))$. For small angles we can write $d y / d r=-P /(2 \pi h G r)$. Integrate this expression and evaluate the constant of integration using the condition that $y=0$ at $r=r_\sigma$. From the result compute the deflection $y=\delta$ of the plug.