Question
A short linear object of length $L$ lies on the axis of a spherical mirror of focal length of $f$ at a distance $u$ from the mirror. Its image has an axial length $L^{\prime}$ equal to $\ldots \ldots \ldots$..(A) $\mathrm{L}[\mathrm{f} /(\mathrm{u}-\mathrm{f})]^{2}$(B) $\mathrm{L}[(\mathrm{u}-\mathrm{f}) / \mathrm{f}]^{2}$(C) $\mathrm{L}[(\mathrm{u}+\mathrm{f}) / \mathrm{f}]^{1 / 2}$(D) $L[f /(u-f)]^{1 / 2}$
Step 1
Step 1: We start with the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$, where $v$ is the image distance, $u$ is the object distance, and $f$ is the focal length of the mirror. Show more…
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Ray Optics and Optical Instruments
Round 1
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