We can use the equation for horizontal motion, which is $x = v_{0x}t$, where $x$ is the horizontal distance, $v_{0x}$ is the initial horizontal velocity, and $t$ is the time. We know that $x = 3000$ ft and $v_{0x} = v_0 \cos(\theta)$, where $v_0 = 1200$ ft/s is
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