Recall that the norm squared of a vector $\mathbf{v}$ is given by $\|\mathbf{v}\|^2 = \langle \mathbf{v}, \mathbf{v} \rangle$. Therefore, we have:
$$ \|\mathbf{x}+\mathbf{y}\|^2 = \langle \mathbf{x}+\mathbf{y}, \mathbf{x}+\mathbf{y} \rangle $$
$$
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