00:01
So the question asks, if you're given a matrix a, and then you're given matrix b, which is a single elementary row operation away from a, is there a way to get back to matrix a? so to do that, let's look at a simple case.
00:26
We'll look at a single matrix, and then we'll gather a generalization from there.
00:33
So let's say we had the matrix.
00:37
Let's do 2, 3, 1, 4.
00:41
There are three elementary row operations, if you can recall them.
00:44
The first one is simply swapping two rows.
00:53
The second, the second is scaling any row by a constant number.
01:11
And the third is adding a scaled multiple of another row.
01:24
So that'll give you, for taking this matrix, that will give you three different matrix matrices so if we look at the first one if we just swap the rows you get the matrix one four two three if we scale by a multiple i will use the number two just for ease i'll do and i'll write it right above it so this one i just did our one swap r2 that one on the wrong side this one i'll do r1 multiplied by two we get four six one four and the last one if we do that one i'll do again two is for ease so r we do r2 goes to r1 plus r2 two two three two three and it's gonna be five ten and then the choice of two was just for ease since i already have them here so now let's look it going from here backwards.
03:00
So this one is actually, i think you could probably see it yourself.
03:04
If you just swap them back, you'll get the matrix you started with.
03:12
For this one, for this one, well, what if we just, so if we have r1 is now equal to two times the original r1, so we'll call it r1 minus, well if i just do, if i just divide it by two, i'm back to where i started.
03:40
So i will do r1 is one half r1...