00:01
Given u equals x squared plus y squared, u sub xx would be equal to 2, u sub y, y would be equal to 2, which would mean that this would equal to 2 plus 2, which is 4, which is not equal to 0, so it's not a solution.
00:29
For b, given u equals x squared minus y squared, u sub xx is 2, u sub y, y, is negative 2, which would give us 2 plus negative 2, which is 0, so this is a solution.
00:48
For c, u sub x would be 3x squared plus 3y squared.
00:57
So u sub double x would be 6x, and u sub y would be 6x, which would mean u sub yy is equal to 6x.
01:10
U sub x, u sub x plus u sub y sub y is 12x, which would mean u sub y is 2x ,000.
01:14
Which is not equal to 0 in general, so not a solution.
01:23
For d, we have u equals a natural log of the square root of x squared plus y squared, which would be equal to one half times a natural log of x squared plus y squared.
01:36
This function's known to be harmonic away from the origin, but you can also verify that this equals zero.
01:46
So this is a solution.
01:48
And particularly for when xy is not equal to zero zero.
02:00
Given u equals sine x times the hyperbolic cosine of y plus cosine x times the hyperbolic sign of y, the second derivative of sine of x is negative sine x and the second derivative of cosine x is negative cosine x and the second derivative of the hyperbolic cosine of y would be cosine hyperbolic cosine y...