Question
(a) Show that the function$f(x)=\sum_{n=0}^{\infty} \frac{x^{n}}{n !}$is a solution of the differential equation(b) Show that $f(x)=e^{x}$
Step 1
The derivative of a sum is the sum of the derivatives, so we can differentiate term by term: \[f^{\prime}(x)=\sum_{n=1}^{\infty} \frac{n x^{n-1}}{n !}\] Show more…
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