Question
(a) Show that the mass inside the Hubble sphere $M_{\mathrm{H}}$ grows as $R^{3 / 2}$ in a matter-dominated model. Find the corresponding rate of growth in the radiation-dominated case.(b) Perturbation $\delta \rho / \rho$ grow proportional to $R$ in the matter-dominated case and proportional to $R^2$ in the radiation-dominated case. For perturbations $(\delta \rho / \rho)_t$ outside the horizon at time $t$ show that in both radiation-dominated and matter-dominated models$$\left(\frac{\delta \rho}{\rho}\right)_t=M_{\mathrm{H}}^{-2 / 3}\left(\frac{\delta \rho}{\rho}\right)_{\mathrm{H}} .$$
Step 1
Step 1: In a matter-dominated model, the mass inside the Hubble sphere $M_{\mathrm{H}}$ is given by $M_{\mathrm{H}} = \frac{4}{3}\pi \rho R_{\mathrm{H}}^3$, where $\rho$ is the density of matter and $R_{\mathrm{H}}$ is the Hubble radius. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For a flat and radiation dominated Universe, the Friedmann equation becomes (dot{a}(t)/a(t))^2 = H^2(t) = (8pi G/3) ho_{rad}(t) where a(t) is the expansion factor, H is the Hubble constant, G is the gravitational constant, and ho_{rad}(t) is the density due to radiation. H_0 is the Hubble constant at the present time when the radiative pressure is ho_{rad,0}. By using the property that ho_{rad}(t) propto a^{-4}(t), show that the expansion factor a(t) can be expressed as a(t) = (t/t_0)^{1/2} where t_0 is the age of the Universe that will be defined as a function of H_0. We will consider that at t = 0, a(0) = 0.
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD