A simple, batch fermentation of an aerobic bacterium growing on methanol gave the results shown in the table. Calculate:
a. Maximum growth rate $\left(\mu_{\max }\right)$
b. Yield on substrate $\left(Y_{X / S}\right)$
c. Mass doubling time $\left(t_{d}\right)$
d. Saturation constant $\left(K_{s}\right)$
e. Specific growth rate $\left(\mu_{n e t}\right)$ at $t=10 \mathrm{~h}$
$$
\begin{array}{cll}
\hline \text { Time (h) } & X(\mathrm{~g} / \mathrm{l}) & S(\mathrm{~g} / \mathrm{l}) \\
\hline 0 & 0.2 & 9.23 \\
2 & 0.211 & 9.21 \\
4 & 0.305 & 9.07 \\
8 & 0.98 & 8.03 \\
10 & 1.77 & 6.8 \\
12 & 3.2 & 4.6 \\
14 & 5.6 & 0.92 \\
16 & 6.15 & 0.077 \\
18 & 6.2 & 0 \\
\hline
\end{array}
$$