Question

A simple harmonic one-dimensional oscillator has energy levels $E_n=$ $(n+1 / 2) \hbar \omega$, where $\omega$ is the characteristic oscillator (angular) frequency and $n=0,1,2, \ldots$. (a) Suppose the oscillator is in thermal contact with a heat reservoir at temperature $T$, with $\frac{k T}{\hbar \omega} \ll 1$. Find the mean energy of the oscillator as a function of the temperature $T$. (b) For a two-dimensional oscillator, $n=n_x+n_y$, where $$ E_{n_x}=\left(n_x+\frac{1}{2}\right) \hbar \omega_x, \quad E_{n_y}=\left(n_y+\frac{1}{2}\right) \hbar \omega_y, $$ $n_x=0,1,2, \ldots$ and $n_y=0,1,2, \ldots$, what is the partition function for this case for any value of temperature? Reduce it to the degenerate case $\omega_x=\omega_y$. (c) If a one-dimensional classical anharmonic oscillator has potential energy $V(x)=c x^2-g x^3$, where $g x^3 \& c x^2$, at equilibrium temperature $T$, carry out the calculations as far as you can and give expressions as functions of temperature for 1) the heat capacity per oscillator and 2) the mean value of the position $x$ of the oscillator.

   A simple harmonic one-dimensional oscillator has energy levels $E_n=$ $(n+1 / 2) \hbar \omega$, where $\omega$ is the characteristic oscillator (angular) frequency and $n=0,1,2, \ldots$.
(a) Suppose the oscillator is in thermal contact with a heat reservoir at temperature $T$, with $\frac{k T}{\hbar \omega} \ll 1$. Find the mean energy of the oscillator as a function of the temperature $T$.
(b) For a two-dimensional oscillator, $n=n_x+n_y$, where
$$
E_{n_x}=\left(n_x+\frac{1}{2}\right) \hbar \omega_x, \quad E_{n_y}=\left(n_y+\frac{1}{2}\right) \hbar \omega_y,
$$
$n_x=0,1,2, \ldots$ and $n_y=0,1,2, \ldots$, what is the partition function for this case for any value of temperature? Reduce it to the degenerate case $\omega_x=\omega_y$.
(c) If a one-dimensional classical anharmonic oscillator has potential energy $V(x)=c x^2-g x^3$, where $g x^3 \& c x^2$, at equilibrium temperature $T$, carry out the calculations as far as you can and give expressions as functions of temperature for
1) the heat capacity per oscillator and
2) the mean value of the position $x$ of the oscillator.
Show more…
Problems and Solutions on Thermodynamics and Statistical Mechanics
Problems and Solutions on Thermodynamics and Statistical Mechanics
U.S.T. of China… 1st Edition
Chapter 2, Problem 130 ↓

Instant Answer

verified

Step 1

The energy levels are given by: \[ E_n = \left(n + \frac{1}{2}\right) \hbar \omega \] The partition function \( Z \) is given by: \[ Z = \sum_{n=0}^{\infty} e^{-\beta E_n} = \sum_{n=0}^{\infty} e^{-\beta \left(n + \frac{1}{2}\right) \hbar \omega} \] where \( \beta  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
A simple harmonic one-dimensional oscillator has energy levels $E_n=$ $(n+1 / 2) \hbar \omega$, where $\omega$ is the characteristic oscillator (angular) frequency and $n=0,1,2, \ldots$. (a) Suppose the oscillator is in thermal contact with a heat reservoir at temperature $T$, with $\frac{k T}{\hbar \omega} \ll 1$. Find the mean energy of the oscillator as a function of the temperature $T$. (b) For a two-dimensional oscillator, $n=n_x+n_y$, where $$ E_{n_x}=\left(n_x+\frac{1}{2}\right) \hbar \omega_x, \quad E_{n_y}=\left(n_y+\frac{1}{2}\right) \hbar \omega_y, $$ $n_x=0,1,2, \ldots$ and $n_y=0,1,2, \ldots$, what is the partition function for this case for any value of temperature? Reduce it to the degenerate case $\omega_x=\omega_y$. (c) If a one-dimensional classical anharmonic oscillator has potential energy $V(x)=c x^2-g x^3$, where $g x^3 \& c x^2$, at equilibrium temperature $T$, carry out the calculations as far as you can and give expressions as functions of temperature for 1) the heat capacity per oscillator and 2) the mean value of the position $x$ of the oscillator.
Close icon
Play audio
Feedback
Powered by NumerAI
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever