00:01
We're given an oscillator that has a spring constant of 5 newtons per meter, an amplitude of oscillation of 0 .1 meters, a maximum speed to v0 equals 4 .2 meters per second.
00:24
And we're asked to find the speed when we're at a position of 5 centimeters.
00:32
So find v when x equals 5 centimeters.
00:43
So how do we do this? well, we can come up with an equation here.
00:54
So our position equation will look something like x equals a times the cosine of omega -t.
01:06
But we don't know omega yet here.
01:12
Luckily, we're going to be able to find that by looking at our velocity formula, which will just be negative a times omega times the sign of omega t.
01:24
And if you're familiar with calculus, the velocity formula is just the derivative of the position formula.
01:31
And if we look at this velocity formula, this a omega here is our amplitude.
01:41
So we can use it to find omega.
01:46
We say a omega equals v0.
01:51
We solve this for omega.
01:53
Omega equals v0 over the amplitude.
01:58
V0 was 4 .2 meters per second...