Question
A simple harmonic progressive wave is represented by the equation $y=8 \sin 2 \pi(0.1 x-2 t)$ where $x$ and $y$ are in $\mathrm{cm}$ and $t$ is in seconds. At any instant the Phase difference between two particles separated by $2.0$ $\mathrm{cm}$ in the $x$-direction is(a) $18^{\circ}$(b) $36^{\circ}$(c) $54^{\circ}$(d) $72^{\circ}$
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1 x-2 t)$. This equation is in the form of $y=a \sin(kx-\omega t)$, where $a$ is the amplitude, $k$ is the wave number, and $\omega$ is the angular frequency. Show more…
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A simple harmonic progressive wave is represented by the equation $y=8 \sin 2 \pi(0.1 x-2 t)$ where, $x$ and $y$ are in $\mathrm{cm}$ and $t$ is in seconds. At any instant the phase difference between two particles separated by $2.0 \mathrm{~cm}$ in the $X$ -direction is (a) $18^{\circ}$ (b) $54^{\circ}$ (c) $36^{\circ}$ (d) $72^{\circ}$
Equation for a progressive harmonic wave is given by $\mathrm{y}=8 \sin 2 \pi(0.1 \mathrm{x}-2 \mathrm{t})$, where $\mathrm{x}$ and $\mathrm{y}$ are in $\mathrm{cm}$ and $\mathrm{t}$ is in seconds. What will be the phase difference between two particles of this wave separated by a distance of $2 \mathrm{~cm} ?$ (A) $18^{\circ}$ (B) $36^{\circ}$ (C) $72^{\circ}$ (D) $54^{\circ}$
For the travelling harmonic wave $y(x, t)=2 \cos 2 \pi(10 t-0.008 x+0.35)$ where $x$ and $y$ are in $\mathrm{cm}$ and $t$ is in $\mathrm{s}$. The phase difference between oscillatory motion of two points separated by a distance of $0.5 \mathrm{~m}$ is (a) $0.2 \pi \mathrm{rad}$ (b) $0.4 \pi \mathrm{rad}$ (c) $0.6 \pi \mathrm{rad}$ (d) $0.8 \pi \mathrm{rad}$
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