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A simple pendulum swings about the vertical equilibrium position with a maximum angular displacement of $5^{\circ}$ and period $T .$ If the same pendulum is given a maximum angular displacement of $10^{\circ},$ then which of the following best gives the period of the oscillations?(A) $\frac{T}{2}$(B) $\frac{T}{\sqrt{2}}$(C) $T$(D) 2$T$

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Chapter 8

Oscillations

Oscillatory Motion

00:58

A pendulum is constructed …

02:25

A simple pendulum is 5.00 …

03:07

A clock pendulum oscillate…

02:10

Pendulums. The period of a…

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01:47

An object moves in simple …

01:17

07:47

Review problem. A simple p…

00:56

A simple pendulum oscillat…

04:00

Use dimensional analysis t…

We know that that time period of a simple pendulum is equal to P is equal to five and the road l Y G it depends on the length of the pendulum and the gravitational acceleration. So it has given that initially it gives the maximum angular displacement five degree and time period is city. If the same pendulum is given of maximum angular displacement is 10 degrees, then which of the following best gives the period of oscillations? We know that period doesn't depend on the amplitude. So we can say the period of pendulum remains same, which is equal to P. So this is equal to option C Option C. Well, we have a correct option. Thank you.

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