00:01
Now for this question we're looking at a pendulum and as oscillating in a simple harmonic motion, it has length of 2 .23 meters and we're given that it is mass 6 .74 kilograms and the speed.
00:25
At its equilibrium position i'm going to assume it is at this particular point, the velocity, is 2 .06 meters per second.
00:41
We're going to find a few different properties of this pendulum.
00:48
So the first one would be the period.
00:51
Period is given as 2 pi square root l over g.
00:57
It should be quite easy to find.
01:01
Since we are given the l, which is 2 .23 meters, and we should get this to be about 3 seconds, 3 .00 seconds.
01:19
To find the total energy, right, we just have to consider at the lowest point, which is at the equilibrium point, or the energy is converted into kinetic energy, which is just half mv square.
01:36
We can find this quite simply.
01:41
By putting in the velocity at the equilibrium position and the mass that is given...