00:01
We have a circuit here and we'd like to find the current that is going through to find i0.
00:07
So let's see what we can do here first.
00:10
So we've got our voltage source, here is 200mv, 250mv rather, so we've got 250mv here.
00:21
To figure out what is exactly going through here we have rs plus rb, rs plus rb because they are in series, right, is going to be 1kω plus 250ω is 1250ω.
00:40
Voltage is 250mv, of course that is the current times the resistance, 1 .25kω.
00:53
So our ib is equal to 250mv over 1 .25kω, that's, let's see, 250 over 1 .25, i'll pull up a calculator here, 250 over 1 .25 is 200 of something, but what is that something? it's not just going to be amps, it's got ma divided by, mv divided by kω is going to step us down two things, that's actually going to be microamps, made, microsoft made, yeah, 200 microamps is ib, 100 ib then, 100 times 200 microamps is 20 ,000 microamps which is 20ma, that's great, so coming down here we've got 20ma...