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This is chapter 27 problem number 30.
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We have ionized potassium atom, and it is under the influence of electric and magnetic fields, both of them.
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And we are asked to calculate the speed at which the atom would go undeflected.
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For that to happen, we have to have the electric force acting on the atom equals to the magnetic force, q times e equals qvb, or.
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Also given that this velocities perpendicular to the magnetic field.
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So i'm dropping the sign term when we cancel charges since we have on both sides in order to calculate the electric field.
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Well, here is the equation.
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The speed times the magnitude of the magnetic field gives us the magnitude of the electric field.
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So 4 .5 times 10 to 4 .3 is given to us as the speed...