00:01
For the given problem, we are given the amplitude of electric field of electromagnetic wave, which is emax.
00:08
We have is 20 newton per coolum.
00:14
We would like to use this information to undermine everything we know about this wave.
00:20
We will first find the b max magnetic field, maximum magnetic field, which is emax divided by speed of light, so 20 divided by.
00:31
By speed of light 3 times 10th power 8 meter per second, which gives us a beam max to be 6 .7 times 10 to power minus 8 tesla.
00:44
We can also use electric field to determine the maximum energy density in electromagnetic waves, so which is umex is equal to e nod, emax square, where enod is permittivity of free space, after substituting that value, which is a constant, with emacs square, we get a 3 .55 times 10 to the power minus 9 joules per meter a cube.
01:16
This is our energy density...