00:01
So in this question, we are given this graph, and then from this graph, we have to figure out multiple properties of this wave.
00:09
So let's look at this graph.
00:11
A couple of things we need to read is when different look at the amplitude of it.
00:20
So from the graph, ys is 4 centimeter, but the amplitude and ys has 4 ticks.
00:26
It looks like the amplitude has 5 ticks, so this is 5 .0 centimeters.
00:33
Then we can look at lambda.
00:36
It looks like from this graph that from 0 to 40 is about one period.
00:41
So we will say this is 0 .40 meter.
00:46
And if you are in doubt, you can also go more precisely.
00:50
You can see that we have a peak around 5 cm, and then we have a peak roughly at 45 centimeters.
00:57
So if you subtract them, they are also around 40 centimeters.
01:02
And then we have speed.
01:03
In order to look for the speed, we are given the tension and the mass density, and that is enough for us to calculate the speed, because the speed is tension, 3 .6 md, of the density, which is 25 times 10 to negative 3 kilograms per meter.
01:21
That gives us 12 meter per second.
01:25
Then period.
01:26
Well, we can find period if we already know velocity and wavelength, because period equals 1 over frequency, and a frequent.
01:35
Is velocity over lambda.
01:38
So this is lambda over velocity.
01:47
Lambda is 0 .40 meter, excuse me, and v is 12 meter per second.
01:55
So now we have a period of 0 .032nd.
02:02
Okay, so, so that is a period...