00:01
We first want to find the speed at the bottom of the slope and the coefficient of friction between the horizontal path or the horizontal surface and skier.
00:08
And so we can first take the sum of forces in the y direction for the skier on the slope.
00:14
This would be equal to the mass times the acceleration of y direction, giving us zero.
00:19
This would be equal to the force normal minus the y component of the gravitational force.
00:24
The force normal is then found to be equal to m g cosine of theta and so now we can oh my apologies we can uh we we know that the slope is frictionless so we don't have to include a a friction a friction a friction a force here but once she hits this horizontal path we will have to account for friction so first we can then solve for the force normal.
01:00
We can then apply the newton's second law in the x direction.
01:03
This would be the mass times the acceleration in the x direction.
01:06
This will be equal to mg sine of theta.
01:14
This would be, of course, the acceleration.
01:19
This would of course be the acceleration, or rather the component of the gravitational force that is parallel to the ramp.
01:30
And so the mass is canceled out, and we find that the acceleration and the x direction is equaling g sign of theta.
01:36
This would be equal to 9 .8 meters per second squared multiplied by sign of 32 degrees, the angle of the incline.
01:48
And this is giving us 5 .2 meters per second squared.
01:53
So now we have to find then the final speed at which she is traveling when she reaches the end of, the slope this will be solved through kinematics we can say that then velocity final squared equals velocity initial squared plus two times the acceleration in the x direction multiplied by the length of the incline and so we know that the initial velocity is zero so the final velocity would then be equal to the square root of two multiplied by 5 .2 meters per second squared multiplied by 50 meters.
02:34
And we then find that the final velocity is going to be equal to approximately 22 .8 meters per second.
02:42
So this would be the final velocity at the bottom of the slope for part a.
02:47
For part b, we want to find the coefficient of friction between the horizontal path and the horizontal path and the skier...