Question
A slab $-L<x<L$ is initially at a temperature of $100 \cos (\pi x / 2 L)^{\circ} \mathrm{C}$. For times $t>0$, the surfaces are insulated. Determine the temperature response $T(x, t)$ in the slab.
Step 1
Therefore, the governing equation for this problem is the one-dimensional heat conduction equation: ∂T/∂t = α ∂²T/∂x² where α is the thermal diffusivity of the material. The boundary conditions are: ∂T/∂x |(x=-L) = 0 (insulated surface at x = -L) ∂T/∂x |(x=L) Show more…
Show all steps
Your feedback will help us improve your experience
Nick Johnson and 71 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The two faces of the slab $0 \leqq x \leqq L$ are kept at temperature zero, and the initial temperature of the slab is given by $u(x, 0)=A$ (a constant) for $0<x<L / 2, u(x, 0)=0$ for $L / 2<x<L$. Derive the formal series solution $u(x, t)=$ $$ \frac{4 A}{\pi} \sum_{n=1}^{\infty} \frac{\sin ^{2}(n \pi / 4)}{n} \exp \left(-n^{2} \pi^{2} k t / L^{2}\right) \sin \frac{n \pi x}{L} $$
Fourier Series Methods and Partial Differential Equations
Heat Conduction and Separation of Variables
At $t=0$, two flat slabs each $5 \mathrm{~cm}$ thick, one at $0^{\circ}$ and one at $20^{\circ}$, are stacked together, and then the surfaces are kept at $0^{-}$. Find the temperature as a function of $x$ and $t$ for $t>0$.
PARTIAL DIFFERENTIAL EQUATIONS
The diffusion or heat flow equation; heat flow in a bar or slab
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD