00:01
Hello friend as soon in the figure there is a slider rod of length l and weight w pyivated at one end as shown in the figure it is released from rest so initial velocity is zero and it is in horizontal position and swims freely when released we have to calculate angular velocity and a reaction at pyovation point a when it is passing horizontal position in b part we have to find angular velocity and reaction for weight of the rod to be 1 .8 pound and length to be three -fifid at horizontal position the weight will act at c point when it is passing through the vertical position at this position weight will be at c point and c point is moving with velocity v and angular velocity omega and weight will act here.
01:58
So this problem can be solved by applying work energy theorem for horizontal position v1 is 0, omega 1 is 0.
02:34
So total kinetic energy is also zero.
02:43
For vertical position v2 will be omega 2 ly2.
03:02
So total kinetic energy at vertical position is half m v2 square plus half i omega 2 square v2 square v2 can be written as omega 2 l by 2 square moment of inertia is m l square by 12 so on solving it total energy you will get 1 by 6 m l square omega 2 square now work energy theorem we have to apply according to work energy theorem worked on by gravitational force is called to change in kinetic energy.
04:21
This will be mg, ly2 is called to 1 .6, ml, n, n, 2, omega 2, 0.
04:39
On solving it, omega 2 you will get root of 3g by n.
05:00
Now see the reaction at a...