A slide projector has a converging lens whose focal length...

A slide projector has a converging lens whose focal length is $105.00 \mathrm{~mm} .$ (a) How far (in meters) from the lens must the screen be located if a slide is placed $108.00 \mathrm{~mm}$ from the lens? (b) If the slide measures $24.0 \mathrm{~mm} \times 36.0 \mathrm{~mm}$, what are the dimensions (in $\mathrm{mm}$ ) of its image?

A slide projector has a converging lens whose focal length is $105.00 \mathrm{~mm} .$ (a) How far (in meters) from the lens must the screen be located if a slide is placed $108.00 \mathrm{~mm}$ from the lens?
(b) If the slide measures $24.0 \mathrm{~mm} \times 36.0 \mathrm{~mm}$, what are the dimensions (in $\mathrm{mm}$ ) of its image?

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Key Concepts

Magnification

Magnification is defined as the ratio of the height of the image to that of the object, and it can also be expressed in terms of distances as m = di/do. It provides a measure of how much larger or smaller the image is compared to the original object, enabling calculations of image dimensions based on the object dimensions.

Converging Lenses

Converging lenses, also known as convex lenses, are optical elements that bring parallel rays of light to a focus. They are characterized by a positive focal length and are used in devices such as slide projectors to form images by bending light rays so that they converge to a point at the focal plane.

Lens Equation

This is a fundamental relationship in optics described by the equation 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the distance from the object to the lens, and di is the distance from the lens to the image. It allows us to determine the image distance when the object distance and focal length are known, and vice versa.

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