00:02
So we are dealing with diffraction here.
00:04
The width of the aperture is 0 .24 millimeter.
00:10
The wavelength incident is 540 nanometers, so within visible range.
00:16
And it falls on a screen at a distance of 3 meters.
00:24
Now, if you want to find out the distance at which we see the first minimum, let's call this angle theta.
00:34
Now, if this distance is x.
00:36
Now because angle theta is very small, we can write that theta is equal to x by the three meters, which is the distance between the screen and the aperture.
00:47
Now, we know that for diffraction, sine theta is equal to m lambda by d.
00:55
For order one, it's simply lambda by d.
00:59
So now because theta is very small, we can equate...