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A small bead of mass $m$ is constrained to slide withoutfriction inside a circular vertical hoop of radius $r$ whichrotates about a vertical axis(Fig. 54 at a frequency $f$ .(a) Determine the angle $\theta$where the bead will be inequilibrium - that is, whereit will have no tendency tomove up or down along thehoop. $(b)$ If $f=2.00 \mathrm{rev} / \mathrm{s}$and $r=22.0 \mathrm{cm},$ what is $\theta$ ?(c) Can the bead ride ashigh as the center of thecircle $\left(\theta=90^{\circ}\right) ?$ Explain.

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a. $\cos ^{-1}\left(g / \omega^{2} \gamma\right)$b. $73^{\circ} 35^{\prime} B 2.74^{\prime \prime}$c. $90^{\circ}$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Cornell University

Rutgers, The State University of New Jersey

Hope College

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

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A small bead of mass $m$ i…

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A small bead of mass m is …

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A single bead can slide wi…

A small bead can slide wit…

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17:05

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A bead slides without fric…

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Hi, friends. This is the problem. Based on motion in a vertical circuit Here it is given a vertical do off radius R. So this is a vertical look off radius R, which is rotating with frequency F. Inside there is a beat which is sliding. So we have to fight it ST up for Did not having that tendency to move up In second part, we have to find the value of theater. If frequency is two revolutions per second edit radius story continue to centimeter omega three toe fight f not to see it. So this angle theater were supposed to make it not a struggle forces acting on it the weight and direct vertically down one. This between the normal reaction here and this will be angled. Zito did. We did move in our original circuit, half areas. Our sign oxygen so it will experience sent difficult force. Am Omi Guys, where are Sign up, Tito, You can resolve the normal force and two components that is an consider. And here it will be and sensitive so at equilibrium and cause off theater toe equal to M G and and sign off sitter Toby am, Omega Square art sign off the door. So from equation Bannon toe we can write and I locked it upon. And of course, Tito, I am Omega Square are signed off theater upon energy for solving it Course of theater. You will get g upon whom you guys split up. Aunt Tita can be written. It's caused in worse off G upon full quite square f square part. This is the answer off part eight. Be Pardon Peter. We have to find causes much G is nine pointed by 3.14 Frequency two revolutions per second. Ladies is 0.22 m. So this anger we will get 73.6 degrees in third part c Okay, Cheetah beat Nigeria. Let us see here not perceive it. Yeah, if Teeter Toby 90 TV then Normal force Bilby How rejected Get balanced by Yeah am whom? You guys were our sign off 19 So beat empty after beach Mhm cannot be balanced. So it couldn't remain in equilibrium. Hence could not that remain and equitably, That's all. Thanks for watching it

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