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Hi.
00:02
In the given problem here this is the inclined plane, the rough inclined plane, which is having an inclination of 37 degree from the horizontal.
00:19
Then here this is a spring and the block which is compressing the spring.
00:28
When this block will be released over this rough inclined surface, it is given that the maximum height the maximum distance covered by the block along the inclined before coming to rest is given as d is equal to 2 .00 meter.
01:06
This will be the situation of the block when it will be moving up.
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It's weight acting vertically downward.
01:15
The component of the weight here this is the vertical the normal component normal to the inclined plane.
01:23
If this angle is theta, this angle will also be theta.
01:25
So this is mg cost theta and this component will be opposing the upward motion of this block.
01:34
The component is mg sine theta.
01:38
Then the normal reaction of the inclined surface over the block n, which is equal to mg cost theta.
01:47
And as the block is moving up, so force of friction, kinetic friction will be acting opposite to its direction of direction of.
01:54
Motion is f k...