Question
A small copper sphere with a radius of $1.00 \mathrm{~cm}$ at a room temperature of $20.0^{\circ} \mathrm{C}$ has a mass density of $8.96 \mathrm{~g} / \mathrm{cm}^{3}$. Calculate the new mass density of the copper sphere after it has been heated to a temperature of $400.0^{\circ} \mathrm{C}$.
Step 1
The change in volume can be calculated using the formula for volume expansion, which is $V_2 = V_1(1 + \gamma \Delta T)$, where $\gamma$ is the coefficient of volume expansion and $\Delta T$ is the change in temperature. Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Gupta and 92 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A copper sphere has a mass of $2.17 \times 10^{3} \mathrm{~g}$, and its volume is $242.2 \mathrm{~cm}^{3}$. Calculate the density of copper.
Chemistry: The Science of Change
The Properties of Matter
What is the radius, $r$, of a copper sphere (density = $\left.8.92 \mathrm{~g} / \mathrm{cm}^{3}\right)$ whose mass is $3.75 \times 10^{3} \mathrm{~g} ?$ 'The volume, $V_{2}$ of a sphere is given by the equation $V=(4 / 3) \pi r^{3}$.
The volume of a copper sphere is $2.56 \mathrm{cm}^{3}$ after being heated from $12^{\circ} \mathrm{C}$ to $984^{\circ} \mathrm{C}$. What was the volume of the copper sphere at $12^{\circ} \mathrm{C} ?$
States of Matter
Solids
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD