A small mirror of area $A$ and mass $m$ is suspended by means of a weightless thread, in vertical plane. On the mirror a beam of light of intensity $I$, is made to incident perpendicular to mirror, due to which mirror is displaced and thread makes a small angle $\alpha$ with the vertical. Assume mirror to be totally reflecting, calculate $\alpha$ :
(a) $\alpha=\frac{2 I A}{c m g}$
(b) $\alpha=\frac{I A}{\mathrm{cmg}}$
(c) $\alpha=\frac{3 I A}{c m g}$
(d) $\alpha:=\frac{L A}{2 c m g}$