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A small object is located 36.0 $\mathrm{cm}$ in front of a concave mirror with a radius of curvature of 48.0 $\mathrm{cm} .$ Where will the image beformed?
Thus, the image distance of the mirror is $\overline{72.0 \mathrm{cm}}$
Physics 103
Chapter 26
Geometrical Optics
Wave Optics
Rutgers, The State University of New Jersey
University of Michigan - Ann Arbor
University of Washington
University of Sheffield
Lectures
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An object $2.00 \mathrm{cm…
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If you place an object $40…
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An object is $36.0 \mathrm…
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A concave mirror has a 48.…
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A 3.0 -cm-tall object is $…
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A concave mirror has a rad…
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. $\mathrm{A} 3 \mathrm{cm…
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A virtual image is formed …
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A virtual image is located…
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A concave mirror has a $40…
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An object is located in ai…
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(a) Find the focal length …
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The placement of an object…
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Where must you place an ob…
Question 25 says a small object is located 36 centimeters in front of a con cave near that has radius of curvature of 48 centimeters. And so I'm gonna go ahead and draw this real quick. The radius of curvature is 48 centimeters, which means the focal distances. Half of that. It's 24 centimeters, and this object is 36 centimeters from it. And so here's our object at 36 centimeters now I do all that so that I can make sure I'm keeping track of everything. My object distance Dio, is positive 36 centimeters because it's in front of the mirror. My focal length is also positive. 24 centimeters. It's also in front of the mirror and the mirror equation, says one over the object distance plus one over the image. Distance is one over the focal length, and so they asked us to find where the image is formed and that's the image distance. And so all I have to do is say, Oh, well, one over D. I is one over F minus one over Dio, and so the inverse button is your friend on your calculator right now. so I'm gonna take 24 in verse minus 36. Inverse. And invert that answer and see that d I is actually 72 centimeters. So what I did was, um, 24 to the negative one minus 36 to the negative one. And then I took that whole thing and I raised it to the negative one power, And that makes the math really easy on your calculator.
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