Question
A small object of mass $m$ carries a charge $q$ and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plate separation is $d .$ If the thread makes an angle $\theta$ with the vertical, what is the potential difference between the plates?
Step 1
The vertical component is equal to the weight of the object, $mg$, and the horizontal component is equal to the electric force on the object, $qE$, where $E$ is the electric field. Show more…
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Review. A small object of mass m carries a charge q and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plate separation is d. If the thread makes an angle $\theta$ with the vertical, what is the potential difference between the plates?
A small object with a mass of $350 . \mu \mathrm{g}$ carries a charge of 30.0 $\mathrm{nC}$ and is suspended by a thread between the vertical plates of a parallel-plate capacitor. The plates are separated by 4.00 $\mathrm{cm} .$ If the thread makes an angle of $15.0^{\circ}$ with the vertical, what is the potential difference between the plates?
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