00:01
You're told that a particle is moving along a semicircle, and there's questions asked about it.
00:07
The first one asks you to show that the force applied on the block is going to be equal to mg cosine theta.
00:20
And they tell you that it's moving with a constant velocity, so that means that all the forces must be balanced, tangent to the path along which the particle is traveling.
00:28
So for this problem, we know that the force of gravity is down, and we know that fg equals mg.
00:37
We know that that force can be broken up into components, one of which will be tangent to the path, and one of which is going to be perpendicular or towards the radius, along the radius of the path.
00:49
And based on the geometry, the problem, you should be able to see that this angle is theta.
00:53
So if i moved this vector, this component, down creating my right triangle, you can see i've created a right triangle here where this side is the adjacent side, this side here.
01:08
And that side is equal to mg, since it's the adjacent to the angle cosine theta.
01:16
And so that means that the applied force faa must also be mg cosine theta, equal in magnitude but opposite in direction so that the velocity is equal to zero.
01:31
There is also a part b in this problem...