A small sphere (emissivity $=0.90,$ radius $=r_{1}$ ) is located at the center of a spherical asbestos shell (thickness $=1.0 \mathrm{~cm},$ outer radius $=r_{2}$ ). The thickness of the shell is small compared to the inner and outer radii of the shell. The temperature of the small sphere is $800.0^{\circ} \mathrm{C},$ while the temperature of the inner surface of the shell is $600.0^{\circ} \mathrm{C},$ both temperatures remaining constant. Assuming that $r_{2} / r_{1}=10.0$ and ignoring any air inside the shell, find the temperature of the outer surface of the shell.