Question
A small spherical object carries a charge of 8.00 $\mathrm{nC}$ . At what distance from the center of the object is the potential equal to 100 $\mathrm{V}$ ? 50.0 $\mathrm{V} ? 25.0 \mathrm{V}$ ? Is the spacing of the equipotentials proportional to the change in potential?
Step 1
Step 1: The electric potential V at a distance r from a point charge q is given by the formula: \[ V = \frac{kq}{r} \] where k is Coulomb's constant, approximately equal to \(9 \times 10^9 \, \mathrm{Nm^2/C^2}\). Show more…
Show all steps
Your feedback will help us improve your experience
Khoobchandra Agrawal and 93 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A small spherical object carries a charge of $8.00 \mathrm{nC} .$ At what distance from the center of the object is the potential equal to $100 \mathrm{V} ? 50.0 \mathrm{V} ? 25.0 \mathrm{V} ?$ Is the spacing of the equip potentials proportional to the change in potential?
A small spherical object carries a charge of $8.00 \mathrm{nC}$. At what distance from the center of the object is the potential equal to $100 \mathrm{~V}$ ? $50.0$ V? $25.0 \mathrm{~V}$ ? Is the spacing of the equipotentials proportional to the change in voltage?
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD