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A small telescope has a concave mirror with a 2.00 m radius of curvature for its objective. Its eyepiece is a 4.00 cm focal length lens. (a) What is the telescope’s angular magnification? (b) What angle is subtended by a 25,000 km diameter sunspot? (c) What is the angle of its telescopic image?

a. $-25$b. $\theta=9.55 \times 10^{-3}$ degreec. $0.239^{\circ}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

Poo P.

April 23, 2020

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angular, but a off the problem. Angola magnification off. The telescope is given by F Is it called you focal end off the objective derided by the focal end of on eyepiece. So deriding these putting these numbers that is a two or a focal meant off objective divided by 44 times. Don't about minus two off the focal went off the eyepiece. This gives us the Anglo magnification off telescope is a 50 in but be handle suspended will be equal to that. There will be two, um 25 triple o derided by 1 49 0.6 times 10 to the power six. The dividing these two numbers gives us 1.67 uh, times 10 to the power minus four radiance. So the angle suspended will be 1.67 times 10 to power for ratings in part C. Um, the angle off the telescope image will be so the family angle off the rafters of image will be many fish in times angle suspended Veta Unification we have is a 50 times the angle suspended we have is 1.67 times 10 to the power of minus four. Then when applying these two numbers gives us eight warned 35 times, 10 to the power minus three. Radiant minus three. Radio radiant.

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