00:01
In this question, we have a smooth sphere of radius r.
00:04
It's made to translate with a constant acceleration, a is equal to g.
00:08
The particle is kept initially at the top of the sphere and released from there with a velocity equal to zero with respect to the sphere.
00:15
We want to find the speed of the particle with respect to the sphere as a function of the angle theta as it slides down.
00:23
So in this diagram, we can see the particle at the top of the sphere, and we can see the particle as it has slid down.
00:29
We know that the force acts on the sphere towards the left, so the particle experiences a pseudo -force equal to m .a.
00:36
Towards the right.
00:37
The initial kinetic energy of the particle is equal to zero, because it starts with zero velocity.
00:43
As a result, using the work energy theorem, we can say that the initial gravitational potential energy is equal to the final kinetic energy, if we take the final position to have zero gravitational potential energy.
00:55
We can also work out the change in height, thus the change in gravitation, potential energy by resolving the components here as seen so that we can say that the change in height so h is equal to r1 minus cosine theta.
01:15
We also know that this distance between here is equal to r sine theta as it's the opposite component to this angle.
01:24
So what we can say now is that the work done by gravity is equal to wg and the work done by the pseudo force is equal to wf...